Applications of Trigonometry Special Triangles There are two special right-angled triangles which you must be able to remember or reproduce. The ratios must ALWAYS given as exact values rather than decimals. 45 0 45 0 30 0 60 0 1 1 Work out what the other measurements must be in these triangles. It may be useful for when you have to reproduce. Access Answers to NCERT Class 10 Maths Chapter 9 – Some Applications of Trigonometry Exercise 9.1 Page No: 203. A circus artist is climbing a 20 m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Selection File type icon File name Description Size Revision Time User; ĉ: Chapter 3 Answer Keys.docx View Download: 89k: v. 2: Nov 5, 2012, 1:09 PM: nesterling.

  1. Applications Of Trigonometry Answer Key
  2. Applications Of Right Triangle Trigonometry Worksheet Answers
  3. Chapter 6 Applications Of Trigonometry Answers

Acces PDF Application Trigonometry Answers Class 10 Maths MCQs Chapter 9 Application of Trigonometry. MCQ On Application Of Trigonometry Class 10 Question 1. The shadow of a tower is equal to its height at 10-45 a.m. The sun’s altitude is (a) 30° (b) 45° (c) 60° (d) 90° Answer/ Explanation. Answer: b Explaination: Reason: Let the height of. Examples of Class 10 Chapter 9 - Some Applications of Trigonometry. Under this section, you will find the solved questions of chapter 9 – Some Applications of Trigonometry from Class 10 Maths textbook along with answer keys. These solutions are available for free PDF download from the given link at Vedantu official. Grade 11 trigonometry problems and questions with answers and solutions are presented. Problems and Questions A ferris wheel with a radius of 25 meters makes one rotation every 36 seconds.

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Trig Answer Keys

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35kv. 1 Jan 21, 2013, 1:07 PMnesterling@littlechute.k12.wi.us
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142kv. 2 Nov 11, 2013, 10:21 AMnesterling@littlechute.k12.wi.us
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91kv. 2 Nov 11, 2013, 10:21 AMnesterling@littlechute.k12.wi.us
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127kv. 2 Nov 13, 2013, 10:34 AMnesterling@littlechute.k12.wi.us
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101kv. 2 Sep 10, 2014, 10:14 AMnesterling@littlechute.k12.wi.us
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234kv. 2 Sep 10, 2014, 10:14 AMnesterling@littlechute.k12.wi.us
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133kv. 2 Nov 18, 2013, 10:52 AMnesterling@littlechute.k12.wi.us
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101kv. 2 Sep 23, 2014, 9:34 AMnesterling@littlechute.k12.wi.us
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100kv. 2 Sep 23, 2014, 7:10 AMnesterling@littlechute.k12.wi.us
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151kv. 2 Dec 2, 2013, 10:53 AMnesterling@littlechute.k12.wi.us
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166kv. 2 Sep 25, 2013, 7:04 AMnesterling@littlechute.k12.wi.us
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122kv. 2 Sep 29, 2014, 7:16 AMnesterling@littlechute.k12.wi.us
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81kv. 2 Oct 1, 2014, 6:49 AMnesterling@littlechute.k12.wi.us
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156kv. 2 Oct 1, 2014, 6:49 AMnesterling@littlechute.k12.wi.us
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556kv. 2 Dec 9, 2013, 9:09 AMnesterling@littlechute.k12.wi.us
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236kv. 3 Dec 16, 2012, 4:37 AMnesterling@littlechute.k12.wi.us
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214kv. 2 Dec 16, 2012, 4:37 AMnesterling@littlechute.k12.wi.us
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95kv. 2 Oct 8, 2014, 7:32 AMnesterling@littlechute.k12.wi.us
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94kv. 2 Oct 9, 2014, 12:28 PMnesterling@littlechute.k12.wi.us
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161kv. 2 Oct 14, 2014, 12:36 PMnesterling@littlechute.k12.wi.us
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333kv. 2 Oct 16, 2014, 10:30 AMnesterling@littlechute.k12.wi.us
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57kv. 2 Oct 16, 2014, 10:32 AMnesterling@littlechute.k12.wi.us
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704kv. 2 Jan 4, 2013, 1:07 PMnesterling@littlechute.k12.wi.us
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1138kv. 2 Oct 27, 2014, 9:43 AMnesterling@littlechute.k12.wi.us
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77kv. 2 Oct 29, 2014, 7:06 AMnesterling@littlechute.k12.wi.us
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128kv. 2 Nov 3, 2014, 1:49 PMnesterling@littlechute.k12.wi.us
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753kv. 2 Jan 14, 2013, 6:03 PMnesterling@littlechute.k12.wi.us
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513kv. 2 Jan 15, 2013, 5:48 PMnesterling@littlechute.k12.wi.us
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515kv. 2 Jan 21, 2013, 3:44 PMnesterling@littlechute.k12.wi.us
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72kv. 2 Sep 17, 2014, 12:08 PMnesterling@littlechute.k12.wi.us
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91kv. 2 Sep 17, 2014, 12:08 PMnesterling@littlechute.k12.wi.us
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119kv. 2 Sep 17, 2014, 12:08 PMnesterling@littlechute.k12.wi.us
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85kv. 2 Sep 17, 2014, 12:08 PMnesterling@littlechute.k12.wi.us
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89kv. 2 Nov 5, 2012, 1:09 PMnesterling@littlechute.k12.wi.us
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475kv. 2 Jan 21, 2013, 3:44 PMnesterling@littlechute.k12.wi.us
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#33 has a mistake.the sin2x should have been replaced with 2sinxcosx 255kv. 2 Nov 5, 2014, 1:12 PMnesterling@littlechute.k12.wi.us
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213kv. 2 Apr 23, 2015, 5:28 AMnesterling@littlechute.k12.wi.us
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131kv. 2 Apr 15, 2015, 10:52 AMnesterling@littlechute.k12.wi.us
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181kv. 2 Oct 22, 2014, 4:05 PMnesterling@littlechute.k12.wi.us
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240kv. 2 Sep 23, 2014, 9:34 AMnesterling@littlechute.k12.wi.us
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276kv. 2 Oct 1, 2014, 5:54 AMnesterling@littlechute.k12.wi.us
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#22 is 1229.42 km 276kv. 2 Oct 9, 2014, 11:22 AMnesterling@littlechute.k12.wi.us
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341kv. 2 Oct 15, 2014, 6:02 AMnesterling@littlechute.k12.wi.us
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350kv. 5 Oct 30, 2014, 1:51 PMnesterling@littlechute.k12.wi.us

Free PDF Download of CBSE Class 10 Maths Chapter 9 Application of Trigonometry Multiple Choice Questions with Answers. MCQ Questions for Class 10 Maths with Answers was Prepared Based on Latest Exam Pattern. Students can solve NCERT Class 10 Maths Application of Trigonometry MCQs with Answers to know their preparation level.

Class 10 Maths MCQs Chapter 9 Application of Trigonometry

MCQ On Application Of Trigonometry Class 10 Question 1. The shadow of a tower is equal to its height at 10-45 a.m. The sun’s altitude is
(a) 30°
(b) 45°
(c) 60°
(d) 90°

Answer/ Explanation

Answer: b
Explaination: Reason: Let the height of tower BC = rm and sun’s altitude = θ
Then Length of its shadow, AB = x m
In rt. ∆ABC, tan θ = (frac{BC}{AB}) = (frac{x}{x}) = 1
⇒ tan θ = tan 450
∴ θ = 45° kof mugen download iso zone

2. In given figure, the value of CE is
(a) 12 cm
(b) 6 cm
(c) 9 cm
(d) 6√3 cm

Answer/ Explanation

Answer: a
Explaination: Reason: In rt. ∆EBC, cos 60° = (frac{BC}{CE})
⇒ (frac{1}{2}) = (frac{6}{CE})
⇒ CE = 12 cm

MCQ Questions For Class 10 Maths Trigonometry Question 3. In given figure, the value of ZC is
(a) 90°
(b) 45°
(c) 30°
(d) 60°

Answer/ Explanation5.4.3 practice applications of trigonometry answers

Answer: d
Cars 3 game download for android. Explaination: Reason: In rt. ∆ABC, cos C = (frac{BC}{AB}) = (frac{7}{14}) = (frac{1}{2})
⇒ cos C = cos 60°
∴ C = 60°

MCQ On Application Of Trigonometry Question 4. In given Fig., the angle of depression from the observing position D and E of the object at A are
(a) 60°, 60°
(b) 30°, 30°
(c) 30°, 60°
(d) 60°, 30°

Answer/ Explanation

Answer: c
Explaination:
Reason: ∵ APD, ∠1 = 90° – 60° = 30°
∴ APE, ∠2 = ∠EAB …[alt Zs]
∴ ∠2 = 60°
Hence the angles of depression at D and E are 30° and 60° respectively.

Some Applications Of Trigonometry Class 10 MCQ Question 5. In given figure, the length of AP is

Answer/ Explanation

Answer: b
Explaination:

MCQ NCERT Application Of Trigonometry Class 10 Question 6. In given figure, the value of AE is

Answer/ Explanation

Answer: a
Explaination: Reason: ∠AED = ∠EAB = 30°
In rt. ∆AED, sin 30° = (frac{AD}{AP})
⇒ (frac{1}{2}) = (frac{45}{AE})
⇒ AE = 90 cm

Trigonometry MCQ Class 10 Question 7. In given figure, AD = 4 cm, BD = 3 cm and CB = 12 cm. The value of tan θ is

Answer/ Explanation

Answer: c
Explaination: Reason: In rt ∆ADB,
AB² = AD² + BD² = (4)² + (3)² = 16 + 9 = 25
∴ AB = √25 = 5
∴ In rt ∆ABC, tan θ (frac{AB}{BC}) = (frac{5}{12})

8. In figure given ABCD is a rectangle, the value of CE is
(a) 1 cm
(b) 2 cm
(c) 3 cm
(d) 4 cm

Answer/ Explanation

Answer: d
Explaination: Reason: Since ABCD is a rectangle
∴ BC = AD = 8 cm and B = 90°
In rt ∆CBE, cos 60° = (frac{CE}{BC})
⇒ (frac{1}{2}) = (frac{CE}{8})
∴ CE = (frac{8}{2}) = 4 cm

Trigonometry MCQ Questions Question 9. In given figure, ABCD is a gm. The lenght of AP is
(a) 2 cm
(b) 4 cm
(c) 6 cm
(d) 8 cm

Answer/ Explanation

Answer: c
Explaination: Reason: Since ABCD is a gm
∴ AD = BC = 4√3
In rt ∆APD, sin 60° = (frac{AP}{AD})
⇒ (frac{sqrt{3}}{2}=frac{mathrm{AP}}{4 sqrt{3}})
⇒ 2AP = 4 × 3 = 12
∴ AP = 6 cm

Applications Of Trigonometry Answer Key

MCQ On Trigonometry For Class 10 With Solutions Question 10. When the length of shadow of a vertical pole is equal to √3 times of its height, the angle of elevation of the Sun’s altitude is
(a) 30°
(b) 45°
(c) 60°
(d) 15°

Answer/ Explanation

Answer: a
Explaination: Reason: Let the height of the vertical pole, BC = h m
∴ Shadow AB = √3 h m and the angle of elevation ZBAC = θ
In rt ∆ABC, tan θ = (frac{B C}{A B}=frac{h}{sqrt{3} h}=frac{1}{sqrt{3}}) = tan 30°
∴ θ = 30°
Hence the Sun’s altitude is 30°

Answers

MCQ Trigonometry Class 10 Question 11. The angle of elevation of top of a tower from a point on the ground, which is 30 m away from the foot of the tower is 30°. The length of the tower is
(a) √3 m
(b) 2√3 m
(c) 5√3m
(d) 10√3 m

Answer/ Explanation

Answer: d
Explaination:

MCQ Questions On Trigonometry For Class 10 Question 12. A plane is observed to be approaching the airport. It is at a distance of 12 km from the point of observation and makes an angle of elevation of 60°. The height above the ground of the plane is
(a) 6√3 m
(b) 4√3 m
(c) 3√3 m
(d) 2√3 m

Answer/ Explanation

Answer: a
Explaination:

Trigonometry Multiple Choice Questions And Answers Pdf Question 13. The upper part of a tree is broken by the wind and makes an angle of 30° with the ground. The distance from the foot of the tree to the point where the top touches the ground is 5 m. The height of the tree is
(a) 10√33 m
(b) 5√33 m
(c) √3 m
(d) √3/5 m

Answer/ Explanation

Answer: b
Explaination:

MCQ On Trigonometry 10th Question 14. The angles of elevation of the top of a rock from the top and foot of 100 m high tower are respectively 30° and 45°. The height of the rock is
(a) 50 m
(b) 150 m
(c) 5o√3m
(d) 50(3 + √3)

Answer

Answer: d

Trigonometry MCQs Question 15. The tops of two poles of height 20 m and 14 m are connected by a wire. If the wire makes an angle of 30° with horizontal, the length of the wire is
(a) 6 m
(b) 10 m
(c) 12 m
(d) 20 m

Answer

Applications Of Right Triangle Trigonometry Worksheet Answers

Answer: c

Chapter 6 Applications Of Trigonometry Answers

We hope the given MCQ Questions for Class 10 Maths Application of Trigonometry with Answers will help you. If you have any query regarding CBSE Class 10 Maths Chapter 9 Application of Trigonometry Multiple Choice Questions with Answers, drop a comment below and we will get back to you at the earliest.